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PHYS2403 Simulation Lab

Experiment 1: Gravity Anomaly Forward Modelling (Buried Sphere)

This web simulation visualises the exact gravity anomaly of a buried spherical body. Change depth, radius, and density contrast to see how the profile amplitude and half-width respond under the sphere model.

Model Parameters

Depth z (m)200 m
Depth is measured to the center of the sphere.
Radius R (m)100 m
Gravity scales with the sphere volume, so R matters strongly.
Δρ (kg/m³)+500
Positive contrast gives a positive anomaly; negative contrast gives a negative anomaly.
Presets
Observation mode

The simulation is for observation only. Use the lab manual for the written questions and analysis.

Subsurface Earth Cross-SectionScale: meters

Gravity meters (surface)Δρ = 500 kg/m³R = 100m, z = 200m200m400m600m800m1000m

Gravity Anomaly Profile (Δg)mGal vs Distance (m)

-1500-1000-500050010001500x½ = 153.3 m
Peak Δg: 0.3494 mGal
Half-width: 153.3 m
Factor: z√(2^(2/3) - 1)

Key Physics Equations

Gravity over Buried Sphere

Δg(x)=43πGR3Δρz(x2+z2)3/2×105 mGal\Delta g(x) = \frac{4}{3}\pi G R^3 \Delta\rho \frac{z}{(x^2 + z^2)^{3/2}} \times 10^5 \text{ mGal}

G6.674×1011 m3/(kgs2)G \approx 6.674 \times 10^{-11} \text{ m}^3/(\text{kg}\cdot\text{s}^2) is the gravitational constant, RR is the sphere radius, zz is depth to the center, Δρ\Delta\rho is the density contrast, and xx is the horizontal distance from the sphere center.

Exact Half-Width Rule

x1/2=z22/310.76642zx_{1/2} = z \sqrt{2^{2/3} - 1} \approx 0.76642 z

This represents the exact half-amplitude distance for the buried-sphere profile, allowing the depth to be estimated as: z=x1/222/31z = \frac{x_{1/2}}{\sqrt{2^{2/3} - 1}}.